Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:32Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
276K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
129K
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
191K
\lim_{α\to 0} \frac{\sin α}{α} = 1
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}