Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:24Z
∇²α = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
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6φ² + 8φ + 4 = 0
∂φ/∂φ = 1φ
det| 11 9 ; 5 12 | = 87
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det| 4 8 ; 1 5 | = 12
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
7φ² + 2φ + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O