Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:16Z
∑_{k=1}^{n} k = n(n+1)/2
det| 6 6 ; 3 7 | = 24
479K
3β² + 6β + 2 = 0
det| 7 2 ; 7 8 | = 42
129K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
1K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
153K
∫₀^∞ e^(-x²) dx = √π / 2
473K
det| 9 4 ; 1 10 | = 86
338K