Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:41Z
2ψ² + 5ψ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
479K
N₂ + 3H₂ ⇌ 2NH₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
129K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∑_{k=1}^{n} k = n(n+1)/2
191K
∇²z = 0
det| 9 4 ; 1 10 | = 86
1K
\oint_C \vec{F}\cdot d\vec{r} = 0
153K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
473K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
338K