Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:55Z
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
75K
3β² + 6β + 2 = 0
F = ma
∫₀^∞ e^(-t²) dt = √π / 2
191K
det| 5 3 ; 7 6 | = 9
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\frac{8}{7} \sum_{i=1}^{n} i^{2}
1x² + 5x + 7 = 0
det| 7 4 ; 4 8 | = 40
338K
∇²ψ = 0
det| 5 9 ; 0 6 | = 30
188K
det| 7 2 ; 3 8 | = 50
416K
3φ² + 8φ + 6 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}