Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:20Z
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
75K
∑_{k=1}^{n} k = n(n+1)/2
479K
8β² + 2β + 0 = 0
∫₀^∞ e^(-n²) dn = √π / 2
129K
∑_{k=1}^{n} k = n(n+1)/2
\lim_{β\to 0} \frac{\sin β}{β} = 1
191K
\lim_{r\to 0} \frac{\sin r}{r} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
1K
det| 12 1 ; 1 13 | = 155
\frac{2}{2} \sum_{i=1}^{n} i^{2}
473K
det| 9 4 ; 1 10 | = 86
338K
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-θ²) dθ = √π / 2
det| 5 5 ; 2 6 | = 20
e^{i\pi} + 1 = 0