Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:23Z
∇²α = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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det| 5 6 ; 2 6 | = 18
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6φ² + 8φ + 4 = 0
det| 4 8 ; 3 5 | = -4
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∂φ/∂φ = 1φ
\lim_{α\to 0} \frac{\sin α}{α} = 1
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det| 4 8 ; 1 5 | = 12
det| 1 4 ; 3 2 | = -10
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det| 9 4 ; 1 10 | = 86
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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
7φ² + 2φ + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²r = 0