Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 22:48Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
12β² + 9β + 3 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
276K
∂z/∂n = 8z
e^{i\pi} + 1 = 0
det| 10 4 ; 1 11 | = 106
153K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
473K
det| 9 4 ; 1 10 | = 86
338K
2H₂ + O₂ → 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
188K
∫₀^∞ e^(-ψ²) dψ = √π / 2