Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:58Z
2ψ² + 5ψ + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
det| 10 2 ; 1 11 | = 108
191K
∇²z = 0
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
473K
det| 4 6 ; 4 5 | = -4
338K
8t² + 2t + 3 = 0