Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 18:01Z
6r² + 7r + 2 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∑_{k=1}^{n} k = n(n+1)/2
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F = ma
det| 10 7 ; 3 11 | = 89
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∫₀^∞ e^(-n²) dn = √π / 2
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det| 3 7 ; 1 4 | = 5
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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det| 7 4 ; 4 8 | = 40
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ΔS ≥ 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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ω = 2πf
e^{i\pi} + 1 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
F = ma
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂