Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:21Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
479K
3β² + 6β + 2 = 0
det| 11 5 ; 0 12 | = 132
276K
det| 11 9 ; 0 12 | = 132
129K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 1 4 ; 0 2 | = 2
153K
det| 7 9 ; 1 8 | = 47
473K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
338K
det| 9 4 ; 1 10 | = 86
188K