Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:56Z
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
479K
3β² + 6β + 2 = 0
\lim_{α\to 0} \frac{\sin α}{α} = 1
276K
det| 7 4 ; 4 8 | = 40
129K
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
\frac{2}{2} \sum_{i=1}^{n} i^{2}
338K
∑_{k=1}^{n} k = n(n+1)/2
188K