Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 19:26Z
∂r/∂φ = 2r
∫₀^∞ e^(-x²) dx = √π / 2
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e^{i\pi} + 1 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\oint_C \vec{F}\cdot d\vec{r} = 0
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det| 9 4 ; 1 10 | = 86
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\oint_C \vec{F}\cdot d\vec{r} = 0
det| 4 6 ; 4 5 | = -4
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