Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 22:24Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\lim_{β\to 0} \frac{\sin β}{β} = 1
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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12β² + 9β + 3 = 0
det| 12 1 ; 4 13 | = 152
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det| 9 4 ; 1 10 | = 86
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∂z/∂n = 8z
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∑_{k=1}^{n} k = n(n+1)/2
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det| 3 3 ; 4 4 | = 0
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