Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:33Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
\lim_{r\to 0} \frac{\sin r}{r} = 1
∑_{k=1}^{n} k = n(n+1)/2
1K
det| 10 9 ; 0 11 | = 110
153K
det| 7 4 ; 4 8 | = 40
473K