Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:14Z
11t² + 7t + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
326K
det| 3 6 ; 0 4 | = 12
198K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
CH₄ + 2O₂ → CO₂ + 2H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-ψ²) dψ = √π / 2
263K
det| 10 1 ; 4 11 | = 106
e^{i\pi} + 1 = 0