Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:22Z
∑_{k=1}^{n} k = n(n+1)/2
det| 8 6 ; 6 9 | = 36
75K
det| 4 8 ; 3 5 | = -4
479K
8β² + 2β + 0 = 0
det| 9 4 ; 1 10 | = 86
129K
∑_{k=1}^{n} k = n(n+1)/2
\lim_{r\to 0} \frac{\sin r}{r} = 1
∑_{k=1}^{n} k = n(n+1)/2
473K