Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:17Z
det| 3 3 ; 5 4 | = -3
∑_{k=1}^{n} k = n(n+1)/2
75K
∫₀^∞ e^(-ψ²) dψ = √π / 2
479K
∇²β = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
390K
E = mc²
det| 9 4 ; 1 10 | = 86
153K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
473K
det| 3 7 ; 2 4 | = -2
∑_{k=1}^{n} k = n(n+1)/2
188K
det| 7 2 ; 3 8 | = 50
416K
∂t/∂β = 2t
PV = nRT