Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:24Z
∇²α = 0
∑_{k=1}^{n} k = n(n+1)/2
198K
6φ² + 8φ + 4 = 0
∫₀^∞ e^(-n²) dn = √π / 2
63K
∂φ/∂φ = 1φ
∫₀^∞ e^(-φ²) dφ = √π / 2
366K
det| 4 8 ; 1 5 | = 12
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
det| 9 4 ; 1 10 | = 86
263K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-ψ²) dψ = √π / 2
233K
∇²r = 0
det| 12 9 ; 2 13 | = 138
\frac{8}{5} \sum_{i=1}^{n} i^{2}