Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:05Z
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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∫₀^∞ e^(-z²) dz = √π / 2
479K
3β² + 6β + 2 = 0
det| 7 4 ; 4 8 | = 40
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∑_{k=1}^{n} k = n(n+1)/2
129K
F = ma
det| 10 4 ; 1 11 | = 106
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\frac{8}{7} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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det| 4 4 ; 5 5 | = 0
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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