Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:28Z
∇ × E = −∂B/∂t
\binom{n}{k} = \frac{n!}{k!(n-k)!}
75K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
479K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
det| 10 4 ; 1 11 | = 106
276K
det| 3 6 ; 0 4 | = 12
129K
F = ma
det| 6 6 ; 3 7 | = 24
390K
10n² + 4n + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-γ²) dγ = √π / 2
∂ω/∂z = 1ω
det| 6 9 ; 4 7 | = 6
det| 9 5 ; 1 10 | = 85