Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:41Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 11 4 ; 5 12 | = 112
191K
\lim_{r\to 0} \frac{\sin r}{r} = 1
\frac{2}{2} \sum_{i=1}^{n} i^{2}
1K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
153K
det| 12 1 ; 1 13 | = 155
det| 11 9 ; 5 12 | = 87
473K
\lim_{t\to 0} \frac{\sin t}{t} = 1
N₂ + 3H₂ ⇌ 2NH₃