Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:50Z
2ψ² + 5ψ + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
276K
∫₀^∞ e^(-t²) dt = √π / 2
129K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
det| 10 4 ; 1 11 | = 106
191K
∇²z = 0
det| 11 5 ; 0 12 | = 132
1K
N₂ + 3H₂ ⇌ 2NH₃
d/dy [y^11] = 11y^10
188K
det| 7 4 ; 4 8 | = 40
416K