Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:29Z
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
479K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
F = ma
10n² + 4n + 5 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
1K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
473K
det| 9 4 ; 1 10 | = 86
338K
∫₀^∞ e^(-γ²) dγ = √π / 2
det| 6 9 ; 4 7 | = 6