Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:41Z
2ψ² + 5ψ + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
479K
N₂ + 3H₂ ⇌ 2NH₃
\frac{12}{6} \sum_{i=1}^{n} i^{2}
276K
∫₀^∞ e^(-φ²) dφ = √π / 2
129K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∑_{k=1}^{n} k = n(n+1)/2
191K
∇²z = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
1K
N₂ + 3H₂ ⇌ 2NH₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
473K
8t² + 2t + 3 = 0
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
F = ma