Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 16:51Z
7φ² + 4φ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
∑_{k=1}^{n} k = n(n+1)/2
198K
E = mc²
CH₄ + 2O₂ → CO₂ + 2H₂O
63K
e^{i\pi} + 1 = 0
det| 9 4 ; 1 10 | = 86
201K
∑_{k=1}^{n} k = n(n+1)/2
319K