Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 23:58Z
d/dα [α^11] = 11α^10
\frac{3}{5} \sum_{i=1}^{n} i^{2}
det| 1 1 ; 5 2 | = -3
392K
det| 1 4 ; 3 2 | = -10
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λ = h/p
det| 11 4 ; 5 12 | = 112
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10r² + 3r + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
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det| 5 6 ; 2 6 | = 18
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det| 9 4 ; 1 10 | = 86
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