Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:28Z
∇²α = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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6φ² + 8φ + 4 = 0
∂φ/∂φ = 1φ
det| 7 4 ; 4 8 | = 40
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∑_{k=1}^{n} k = n(n+1)/2
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det| 4 8 ; 1 5 | = 12
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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∫₀^∞ e^(-φ²) dφ = √π / 2
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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²r = 0