Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 01:01Z
\frac{12}{9} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-r²) dr = √π / 2
det| 9 4 ; 1 10 | = 86
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det| 5 3 ; 6 6 | = 12
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
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