Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:49Z
2ψ² + 5ψ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
75K
N₂ + 3H₂ ⇌ 2NH₃
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∑_{k=1}^{n} k = n(n+1)/2
473K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
338K
CH₄ + 2O₂ → CO₂ + 2H₂O
188K