Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 23:40Z
d/dα [α^11] = 11α^10
\frac{3}{5} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
392K
det| 7 4 ; 4 8 | = 40
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λ = h/p
∫₀^∞ e^(-t²) dt = √π / 2
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10r² + 3r + 0 = 0
det| 4 4 ; 5 5 | = 0
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det| 7 6 ; 1 8 | = 50
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∫₀^∞ e^(-φ²) dφ = √π / 2
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