Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 06:42Z
det| 4 5 ; 4 5 | = 0
N₂ + 3H₂ ⇌ 2NH₃
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
det| 7 4 ; 4 8 | = 40
191K
det| 3 7 ; 2 4 | = -2
153K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
473K
∑_{k=1}^{n} k = n(n+1)/2
188K