Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 08:21Z
∑_{k=1}^{n} k = n(n+1)/2
det| 1 4 ; 3 2 | = -10
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∑_{k=1}^{n} k = n(n+1)/2
479K
11n² + 1n + 0 = 0
det| 7 4 ; 4 8 | = 40
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 3 1 ; 7 4 | = 5
191K
4y² + 8y + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
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