Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 19:49Z
∂r/∂φ = 2r
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 9 4 ; 1 10 | = 86
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\oint_C \vec{F}\cdot d\vec{r} = 0
det| 3 1 ; 7 4 | = 5
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∑_{k=1}^{n} k = n(n+1)/2
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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