Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:04Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 6 6 ; 3 7 | = 24
191K
det| 9 4 ; 1 10 | = 86
390K
\lim_{r\to 0} \frac{\sin r}{r} = 1
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
1K
det| 5 6 ; 7 6 | = -12
338K