Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:42Z
2ψ² + 5ψ + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
det| 10 4 ; 1 11 | = 106
276K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
191K
∇²z = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
153K
N₂ + 3H₂ ⇌ 2NH₃
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
473K
8t² + 2t + 3 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
188K
F = ma
∫₀^∞ e^(-φ²) dφ = √π / 2