Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 00:57Z
12r² + 5r + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
iħ ∂ψ/∂t = Ĥψ
11x² + 6x + 2 = 0
det| 9 4 ; 1 10 | = 86
201K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 11 4 ; 5 12 | = 112
176K
det| 7 6 ; 1 8 | = 50
319K
det| 11 9 ; 5 12 | = 87
359K
∑_{k=1}^{n} k = n(n+1)/2
263K