Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:40Z
∇²α = 0
∫₀^∞ e^(-t²) dt = √π / 2
326K
6φ² + 8φ + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
63K
∂φ/∂φ = 1φ
∑_{k=1}^{n} k = n(n+1)/2
366K
det| 4 8 ; 1 5 | = 12
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
319K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
\lim_{α\to 0} \frac{\sin α}{α} = 1
263K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²r = 0