Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:55Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 1 4 ; 0 2 | = 2
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F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\frac{8}{7} \sum_{i=1}^{n} i^{2}
\oint_C \vec{F}\cdot d\vec{r} = 0
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1x² + 5x + 7 = 0
∇²ψ = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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