Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:08Z
∇²α = 0
∫₀^∞ e^(-t²) dt = √π / 2
326K
6φ² + 8φ + 4 = 0
det| 5 3 ; 2 6 | = 24
155K
det| 5 2 ; 3 6 | = 24
63K
∂φ/∂φ = 1φ
det| 9 4 ; 1 10 | = 86
366K
det| 4 8 ; 1 5 | = 12
det| 5 3 ; 7 6 | = 9
176K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²r = 0