Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:34Z
11t² + 7t + 4 = 0
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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CH₄ + 2O₂ → CO₂ + 2H₂O
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
176K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
263K
det| 10 1 ; 4 11 | = 106
\binom{n}{k} = \frac{n!}{k!(n-k)!}
233K