Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:36Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
det| 7 4 ; 4 8 | = 40
479K
3β² + 6β + 2 = 0
det| 6 6 ; 3 7 | = 24
276K
F = ma
CH₄ + 2O₂ → CO₂ + 2H₂O
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
1K
det| 1 1 ; 5 2 | = -3
338K
det| 11 5 ; 0 12 | = 132
188K