Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:39Z
∇ × E = −∂B/∂t
det| 4 8 ; 3 5 | = -4
479K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
276K
F = ma
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
191K
10n² + 4n + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
1K
det| 9 4 ; 1 10 | = 86
153K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-γ²) dγ = √π / 2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
416K
det| 6 9 ; 4 7 | = 6