Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 21:48Z
d/dx [x^11] = 11x^10
det| 1 4 ; 3 2 | = -10
278K
4r² + 1r + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
392K
∫₀^∞ e^(-x²) dx = √π / 2
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∂φ/∂θ = 6φ
∑_{k=1}^{n} k = n(n+1)/2
330K
det| 2 1 ; 7 3 | = -1
det| 9 4 ; 1 10 | = 86
375K
\frac{10}{1} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\oint_C \vec{F}\cdot d\vec{r} = 0
e^{i\pi} + 1 = 0