Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 00:48Z
ω = 2πf
∫₀^∞ e^(-z²) dz = √π / 2
479K
7x² + 6x + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
129K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
390K
5β² + 9β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
1K
det| 9 4 ; 1 10 | = 86
153K
det| 4 4 ; 5 5 | = 0
188K