Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:24Z
11t² + 7t + 4 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
198K
E = mc²
\frac{12}{6} \sum_{i=1}^{n} i^{2}
155K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{t\to 0} \frac{\sin t}{t} = 1
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 7 4 ; 4 8 | = 40
263K
det| 10 1 ; 4 11 | = 106
Fe₂O₃ + 3CO → 2Fe + 3CO₂
233K
det| 7 2 ; 3 8 | = 50
412K
∑_{k=1}^{n} k = n(n+1)/2
iħ ∂ψ/∂t = Ĥψ