Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:05Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
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F = ma
det| 7 4 ; 4 8 | = 40
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\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 5 6 ; 2 6 | = 18
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1x² + 5x + 7 = 0
det| 4 8 ; 1 5 | = 12
∇²ψ = 0