Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:19Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 8 ; 3 5 | = -4
479K
3β² + 6β + 2 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
276K
∑_{k=1}^{n} k = n(n+1)/2
129K
F = ma
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 3 3 ; 4 4 | = 0
153K
1x² + 5x + 7 = 0
det| 10 2 ; 1 11 | = 108
473K
det| 5 9 ; 0 6 | = 30
338K
∇²ψ = 0