Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:18Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 3 7 ; 2 4 | = -2
276K
∑_{k=1}^{n} k = n(n+1)/2
129K
F = ma
\frac{8}{7} \sum_{i=1}^{n} i^{2}
1x² + 5x + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
473K
det| 11 4 ; 5 12 | = 112
338K
∇²ψ = 0