Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:32Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 6 ; 4 5 | = -4
75K
3β² + 6β + 2 = 0
F = ma
det| 9 4 ; 1 10 | = 86
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
153K
CH₄ + 2O₂ → CO₂ + 2H₂O
473K
∫₀^∞ e^(-t²) dt = √π / 2
338K